Question

How do you find the limit (u−1)3(1u−u2+3u−3) as u→1?

Answer 1

(u-1)3 (1u-u2+3u-3

(1-1)3 (1(1)-(1)2+3(1)-3

(0)3 (1-2+3-3)

(0)(-1)

0