Question

How do you find the nature of the roots using the discriminant given x2−7x+12=0?

Answer 1

Hi! ❤

$p(x) = {x}^{2} - 7x + 12$

So, to find the nature of polynomial we know that

${b}^{2} - 4ac$

where b = Coefficient of 2nd term

a= Coefficient of 1st term

c = Coefficient of 3rd term.

${7}^{2} - 4(1) \times 12$

$49 - 4 \times 12$

$49 - 48 = 1$

If the roots are greater than 0 then NO ROOTS WILL EXIST.