Question

How do you find the zeros of the polynomial function with equation f(x)=(x+4)(2x–1)(x–7)?

Answer 1

$f(x) = 0 \\ = > (x + 4)(2x - 1)(x - 7) = 0 \\ (x + 4) = 0 \\ = > x = - 4 \\ (2x - 1) = 0 \\ = > x = 1 \div 2 \\ (x - 7) = 0 \\ = > x = 7 \\ so \: there \: are \: three \: zeroes \:$

= -4, 1/2, 7

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