Question

How do you find three consecutive even integers whose sum is 138?

Answer 1

let the first integer be = x

let the second integer be = (x+1)

let the third integer be =(x+2)

for ex

if x is 1

second integer is 1 + 1= 2

third integer is 2+ 1= 3

now, according to the question,

sum of the integers = 138

so the equation is,

x+(x+1)+(x+2)=138

3x + 3= 138

3x=138-3

3x=135

x=135/3

x=45

so,

first integer = x = 45

second integer = x+1 = 46

third integer = x+2 = 47

hence the integers are 45,46,47