How do you multiply (2r+3)(7r+7)?
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Answered by
9
(2r + 3)(7r + 7)
=> 14r² + 14r + 21r + 21
=> 14r² + 35r + 21
harsh6724:
wrong bro
Answered by
4
(a+b)(a-b)
(2r+3)(7r+7)
2r(7r+7)+3(7r+7)
14r²+14r+21r²+21
35r²+14r+21=0
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