Question

How do you multiply (2x+3)(2x−3)?

Answer 1

HEY USER HERE IS YOUR ANSWER :-

= (2x+3)(2x-3)

= 4x^2 - 6x + 6x - 9 (+6 and -6 cancel each other )

= 4x^2 - 9

HOPe iT HELPS YOU !!!

Answer 2

Answer:

Step-by-step explanation:

MULTIPLICATION IS SIMPLE

take (2x+3)*(2x-3)

Part I: First we take 2x from I bracket and multiply to II bracket

like 2x*(2x-3)

=2x*2x-2x*3

=(2*2)(x*x)-(2*3)*x

=4*x²+6*x=4x²-6x-------(1)

Part II:

Now we take 3 from I bracket and multiply to II bracket

like 3*(2x-3)

=3*2*x-3*3 ( out side 3 is of + and inside -3 is of - so + multiply - is -)

=6*x-9=6x-9 -------(2)

Now We add the result in (1) and (2)

Then we get

(2x+3)(2x-3)

=4x²-6x+(6x-9)

=4x²-6x+6x-9

=4x²-9