How do you solve 2d2+29d−15=0?
Answers
Answered by
5
Solution:
Equation : 2d² +29d -15 = 0
2d² +29d -15 = 0
2d² + 30d - d - 15 = 0
2d(d+15) -1(d+15) = 0
(2d-1)(d+15) = 0
2d - 1 = 0. or. d+15 = 0
Therefore, value of d are ½ and -15.
Answered by
1
Solution:
Quadratic Equation : 2d² +29d -15 = 0
2d² +29d -15 = 0
= 2d² + 30d - d - 15 = 0
= 2d(d+15) -(d+15) = 0
= (2d-1)(d+15) = 0
2d - 1 = 0. d+15 = 0
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