Math, asked by satakshi2926, 1 year ago

How do you solve 2d2+29d−15=0?

Answers

Answered by Anonymous
5

Solution:

Equation : 2d² +29d -15 = 0

2d² +29d -15 = 0

2d² + 30d - d - 15 = 0

2d(d+15) -1(d+15) = 0

(2d-1)(d+15) = 0

2d - 1 = 0. or. d+15 = 0

Therefore, value of d are ½ and -15.

Answered by Awesome98
1

Solution:

Quadratic Equation : 2d² +29d -15 = 0

2d² +29d -15 = 0

= 2d² + 30d - d - 15 = 0

= 2d(d+15) -(d+15) = 0

= (2d-1)(d+15) = 0

2d - 1 = 0. d+15 = 0

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