Math, asked by nandinibhandari8954, 1 year ago

How do you solve 4x ≥ -16 and x + 1 ≤ 0?


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Answers

Answered by kvjkarthik
0

Answer:

x = -1, -2 , -3, -4    or   -4 ≤ x ≤ -1

Step-by-step explanation:

4x≥ -16  &  x+1 ≤ 0

Simplifying,   x ≥ -4  &  x ≤ -1

x∈ { -1, -2 , -3, -4 }   or     -4 ≤ x ≤ -1

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