How do you solve for b when a equals 3b-c?
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a=3b-c
3b=a+c
b=(a+c)/3
3b=a+c
b=(a+c)/3
Answered by
0
a =3b-c
a+c =3b
a+c/3 =b
b =a+c/3
a+c =3b
a+c/3 =b
b =a+c/3
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