Question

How do you solve |x+2|−5≥8?

Answer 1

|X+2|≥13

(X+2)²≥13² [since |X+2|>0]

(X+2)² -13²≥0

(X+15)(X-11)≥0

X+2 ≤ -13 or X+2 ≥ 13

X ≤-15 or X ≥11

Hope this helps!