How does resolving power of a microscope change when diameteris dec?
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The resolving power of a microscope is given by Resolving Power =2μsinβ/1.22λ, where λ is the wavelength of the light used and β is half of the angle subtended by the diameter of the objective of the microscope at the focus. Therefore, resolving power is inversely proportional to the wavelength of the light used. Hope this is what you were looking for.
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plz mark me brainliest
The resolving power of a microscope is given by Resolving Power =2μsinβ/1.22λ, where λ is the wavelength of the light used and β is half of the angle subtended by the diameter of the objective of the microscope at the focus. Therefore, resolving power is inversely proportional to the wavelength of the light used. Hope this is what you were looking for.
thanks
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