How does the volume density of charge vary with the
radius of charged body ?
Answers
Answered by
1
Explanation:
A spherical body that would change the look of our integral and thus change our charge. This is because our differential dq is expressed in terms of the parameters of our body.
Answered by
7
Key concept : According to Gauss' law, the term q
enclosed
on the right side of the equation ϕ
s
E. dS=q
enclosed/in
0
includes the sum of all charges enclosed by the surface called (Gaussian surface).
In left side equation, the electric field is due to all the charges present both inside as well as outside the Gaussian surface.
Hence in given question, E on LHS of the above equation will have a contribution from all charges while q on the RHS will have a contribution from q
2
and q
4
High at sharp and less at flat portion
hope it will help you
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