Question

How fast should a man weighing 600 newton runs so that the kinetic energy is 650 joule?

Answer 1

f=ma

f= 600 a=10

m=f/a

m=600/10

m=60

kinetic energy= 1/2mv^2

650=1/2 x 60 x v^2

650= 30 v^2

65/3 = v^2

21.66 = v^2

v= 4.65m/s

the man should run 4.65 m/s

hope this helps you :)

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