How is 2sinxcosx= sin2x ?
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Here's your answer...
sin 2x can be written as sin(x+x)
sin(a+b) = sin a . cos b + cos a . sin b
Substituting a and b as x...
sin(x+x) = sin x . cos x + cos x . sin x
sin 2x = 2 sin x cos x
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Here's your answer...
sin 2x can be written as sin(x+x)
sin(a+b) = sin a . cos b + cos a . sin b
Substituting a and b as x...
sin(x+x) = sin x . cos x + cos x . sin x
sin 2x = 2 sin x cos x
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Heay your ans is here
sin (2x) = 2sinxcosx
in formula sin(A+B ) = sinA cosB+ cosA sinB
putting A=B
sin(A+A) = sinA cosA+ cosA sinA
then
sin2A = 2sinAcosA
sin (2x) = 2sinxcosx
in formula sin(A+B ) = sinA cosB+ cosA sinB
putting A=B
sin(A+A) = sinA cosA+ cosA sinA
then
sin2A = 2sinAcosA
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