Chemistry, asked by abhimanyu7002, 1 year ago

how is potash alum prepared?

Answers

Answered by patidar
2
Aluminum metal is treated with hot aqueous KOH solution. Aluminium dissolves as potassium aluminate, KAl(OH)4, salt. 2Al(s) + 2KOH(aq) + 6H2O(l)  2KAl(OH)4 (aq) + 3H2 Potassium aluminate solution on treatment with dil. Sulphuric acid first gives precipitate Al(OH)3, which dissolves on addition of small excess of H2SO4 and heating. 2KOH(aq) + H2SO4(aq)  2Al(OH)3 (s) + K2SO4(aq) + 2H2O(l) 2Al(OH)3 (s) + 3 H2SO4(aq)  Al2(SO4)3(aq) +6H2O(l) The resulting solution is concentrated to near saturation and cooled. On cooling crystals of potash alum crystallize out. K2SO4(aq) + Al2(SO4)3(aq) + 24H2O(l)  K2SO4.Al2(SO4)3. 24H2O(s)

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Answered by keshavmpsjaipur
1

Answer:

by heating the powder of it with water and make a super saturated solution and then keep i for cooling then the crystals of the potash alum will be formed

Explanation:

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