Math, asked by sophiaevans, 11 months ago

How is the graph of y=-8x^2-2 different from the graph of y=-8x^2

Answers

Answered by DEVINEQUEEN
0

Answer:

With the function y=8x2 (or really any function), we're taking a series of values of x, dropping them into the function, and getting a yvalue.

In this case, when x=0,y=0, when x=1,y=8, and when x=−10,y=800

So let's now look at y=8x2−1 - how is it different? For each value of x that we put into this function, the resulting value of y will be one less than for the other function.

This gives us when x=0,y=−1, when x=1,y=7, and when x=−10,y=799.

Graphically, they look like this (with the y=8x2nested just above the y=8x2−1):

graph{(y-8x^2)(y-8x^2+1)=0}

Answered by TakenName
0

y=ax²+q is a graph which is moved parallely upwards by q.

So, the graph is y=-8x² moved downwards by 2.

Both graphs don't intersect with each other.

(because both graph don't pass a common point)

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