How is the instrumental broadening is subtracted from xrd peak profile?
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You have to measure the FWHMsample of each peak of your sample (take into account only Ka1 if you don't have Ka2 monochromator) and subtract the instrumental FWHMinst at that particular diffraction angle.
To obtain the instrumental FWHM function of the diffraction angle you can pass a commercial standard for XRD (LaB6 or Al2O3) to determine the FWHMinst. Then fit FWHMinst VS 2teta with a polynome.
(βi)n=(FWHMsample)n-(FWHMinst)n
1<n<2, It depends on the peak profile you used: Gauss, Lorentz or Voigth
To obtain the instrumental FWHM function of the diffraction angle you can pass a commercial standard for XRD (LaB6 or Al2O3) to determine the FWHMinst. Then fit FWHMinst VS 2teta with a polynome.
(βi)n=(FWHMsample)n-(FWHMinst)n
1<n<2, It depends on the peak profile you used: Gauss, Lorentz or Voigth
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