How many moles of helium gas occupy 22.4 l at 30oc and 1 atmosphere?
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Answered by
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P = 1 atm
V = 22.4 l
T = 30℃ = 303k
n = ?
Apply. PV = n RT
1 × 22.4 = n × 0.0821 × 303
n = 22.4 / 24.87
n = 0.900
Hence it contains 0.900 moles.
Thanks
V = 22.4 l
T = 30℃ = 303k
n = ?
Apply. PV = n RT
1 × 22.4 = n × 0.0821 × 303
n = 22.4 / 24.87
n = 0.900
Hence it contains 0.900 moles.
Thanks
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