how long it take a force of 10N to stop a mass of 2.5kg which is moving at 20m/s
Answers
Answered by
4
Answer: 5 seconds
Explanation:
f = ma
10 = 2.5a
a = 4m/s^2
20m/s divided by 4m/s^2 = 5s
Answered by
0
Answer:
force applied(F)= -10N (since the force is acting in the opp. direction of motion or opposing the motion)
mass of body(m)=2.5kg
initial velocity of body(u)=20m/s
final velocity of body(v)=0m/s
According to newton's seond law of motion
F=ma
-10=2.5*a
-10/2.5=v-u/t (since a=v-u/t)
-4t=0-20
t=-20/-4
t=5 sec.
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