Question

How many 176 Ω resistors (in series) are required to carry 5 A on a 220 V line?

Answer 1

Answer:

,

For x number of resistors of resistance 176 Ω,

Here ,Supply voltage, V = 220 V

Current, I = 5 A

Equivalent resistance of the combination = R, given as

$\frac{1}{r} = x \times ( \frac{1}{176} )$

$r = \frac{176}{x}$

From Ohm’s law,

$\frac{v}{i} = \frac{176}{x}$

$x = \frac{176 \times i}{v}$

$x = \frac{176 \times 5}{220}$

$x = 4$

∴four resistors of 176 Ω are required to draw the given amount of current.

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