How many 20 cm by 30 cm rectangular tiles would you need to tile the outdoor area shown below
Answers
Answer:
find surface area of outdoor area and divide it by surface area of tiles
To find the solution for the problem, we must first figure out the area of the complex shape.
The complex shape is a combination of 1 square and 2 rectangles.
The breadth of the bigger rectangle is 4.8 m and one of the sides of the square is 0.9 m.
Since all the shapes have right angles therefore it is known that they are either rectangles or squares.
The length of the bigger rectangle is 2.6m-0.9m= 1.7m
The length of the smaller rectangle is 0.9m
The breadth of the smaller rectangle is
=4.8m-(0.9m+1.7m)
= 4.8m-2.6m
= 2.2m
Length of bigger rectangle is 2.6m-0.9m= 1.7m
Therefore the area of the smaller rectangle is
= length x breadth
= 0.9mx2.2m
= 1.98m2
The area of the bigger rectangle is
= 1.7m x 4.8m
= 8.6m2
The area of the square is
= (0.9m) 2
= 0.81m2
Therefore the complete area is
= 0.81m2+8.6m2+1.98m2
= 11.39m2
The area of the tiles is
= 20cm x 30 CM
= 600cm2
= 600+1000
= 0.6 m2
Therefore the number of tiles needed to cover the whole area is
= 11.39m2+0.6m2
= 18.98
~19 tiles