Math, asked by rajukatiyar, 20 days ago

The area of four walls of a room is 144 m2. If the length of the room is thrice its breadth and the height is 3m. Find the area of the floor ​

Answers

Answered by umeshbaviskar523
0

Step-by-step explanation:

let....

breadth=bm

length=lm=3×b=3bm

height=hm=3m

\begin{gathered}area \: of \: four \: walls = 144 \: sq.m \\ 2h(l + b) = 144 \\ 2(3)(3b + b) = 144 \\ 6(4b) = 144 \\ 4b = \frac{144}{6 } \\ 4b = 24 \\ b = 6 \: m\end{gathered}

areaoffourwalls=144sq.m

2h(l+b)=144

2(3)(3b+b)=144

6(4b)=144

4b=

6

144

4b=24

b=6m

\begin{gathered}l = 3 \: b \\ l = 3(6) \\ l = 18 \: m\end{gathered}

l=3b

l=3(6)

l=18m

\begin{gathered}area \: of \: the \: floor \: = l \times b \\ = 18 \times 6 \\ = 108 \: sq.m\end{gathered}

areaofthefloor=l×b

=18×6

=108sq.m

Answered by isos143geeth
2

Answer:

108m2

Step-by-step explanation:

given -area of four walls =144

area of room =2(l+b)xh

i.e 2( l+b)h = 144

2(l+3l)3= 144

24l = 144

l = 144/ 24

l = 6

hence b = 18

area of floor is 6x18=108 m square

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