how many AG atoms are there in 0.0001 g of ag molar mass of of ag is 108 g per mole
Answers
Answered by
22
given ag weight=0.0001, ag molar mass=108g;
108g of ag has 1 mole of atoms
we know that 1mole has 6.023×10^23 atoms
therefore 0.0001g of ag contains
=(0.0001×6.023×10^23)÷108
=0.05576×10^19
5576×10^14 atoms
If u found it useful then please mark it as the brainliest.
108g of ag has 1 mole of atoms
we know that 1mole has 6.023×10^23 atoms
therefore 0.0001g of ag contains
=(0.0001×6.023×10^23)÷108
=0.05576×10^19
5576×10^14 atoms
If u found it useful then please mark it as the brainliest.
Similar questions