Question

How many Al³+ ions are there in 204g of aluminium oxide​

Answer 1

Explanation:

Now, 27 g of aluminium has ions = 6.022 × 10^23 aluminium ions. So, 0.027 g of aluminium has ions = 6.022 × 10^23 / 27 × 0.027. Thus, the number of aluminium ions (Al³+) in 0.051 gram of aluminium oxide is 6.022 × 10^20

Answer 2

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Aluminum oxide = Al₂O₃

Atomic mass of Al = 27

Atomic mass of Oxygen = 16

There are two atoms of aluminium , hence ,

atomic mass = 27 x 2 = 54

three atoms of oxygen are there , hence ,

atomic mass = 16 x 3 = 48

atomic mass / molar mass of aluminium oxide = 54 + 48 = 102 g

Given mass = 0.051 g

No: of moles = given mass / molar mass

= 0.051 /102 moles

we have a formula to calculate no: of particles in an atom .

The no: of particles can be ions , molecules , etc.

No: of particles = No: of moles x Avogadro no:

As there are 2 atoms of aluminium in aluminium oxide , we multiply the product obtained above with 2.

No: of ions = 0.051/102 x 6.022 x 10²³ x 2

= 6.022 × 10 ²⁰ aluminium ions