How many atom of each constituent elements are present in 50 gram of CaCo3
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50 g CaCO3 will contain = 3 X 6.022 X 10^23 X 50/100 = 9.033 X 10^23
Answered by
1
50 g CaCO3 will contain = 3 X 6.022 X 10^23 X 50/100 = 9.033 X 10^23
Answered by
0
50 g CaCO3 will contain = 3 X 6.022 X 10^23 X 50/100 = 9.033 X 10^23
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