Question

How many atoms are present in 480 g of Ozone

Answer 1

hey
here's your answer!!


Molar mass of Ozone = 3 * 16 = 48.
so 48 g of Ozone contains 1 mole of ozone molecules.
1 mol = 6.022 * 10²³
so 480 g of ozone contains 10 moles of ozone.

So 10 moles of ozone contains 6.022 * 10²³ * 10
= 6.022 * 10²⁴

as each molecule of ozone contains 3 atoms of oxygen , therefore number of atoms in 480 g of Ozone is 6.022 * 10²⁴ * 3 atoms
= 18.066 * 10²⁴.

Hope it helps!!

Answer 2

Number of Moles = 
Given substance mass in g
Molar mass of ozone= 480/48
= 10 moles
Number ofmolecules = moles × avogadro
number
= 10 × 6.022 ×10^23= 6.022 ×10^24
Number of atoms in 1 molecule of ozone = 3
So number of atom molecules = 6.022 × 10^24× 3
= 18.066 × 10^24 atoms