How many atoms are present in a piece of iron that has a mass of 65.0 g/ (atomic mass; Fe = 55.9 amu).
Answers
Answered by
2
Answer:7.002*10 raise to 23
Explanation:No.of moles of iron
65/55.9=1.163
No. of atoms in a mole=6.022×10'23
No. of atoms in 1.163 mol
=1.163*6.022×10'23=7.002×10'23
Answered by
4
1 mole = 6.022×10^23 atoms
Explanation:
no of moles=mass of the element ÷gram atomic mass of the element.
no of moles=65.0/55.9
=1.16 moles(1.163=~1.16)
1.16 moles = 6.022×10^23×1.16
= 6.985×10^23 atoms
#pls mark as brainliest plss
Similar questions