How many atoms are present in a piece of iron that has a mass of 65.0 g/(atomic mass; Fe=55.9 amu).
Answers
Answered by
0
7.0023 to the power of 23
Answered by
12
HEY DEAR.....!!
55.9 moles per g
65.0g/55.9moles/g = 1.16 moles
1.16moles(6.022 x 10^23atoms/mole) = 6.99 x 10^23 atoms
@@@@@@@@@@@@@@@@@@@@@
HOPE IT'S HELP U......!!
55.9 moles per g
65.0g/55.9moles/g = 1.16 moles
1.16moles(6.022 x 10^23atoms/mole) = 6.99 x 10^23 atoms
@@@@@@@@@@@@@@@@@@@@@
HOPE IT'S HELP U......!!
AtulChaudhary:
55.9 not mole it is weight so right answer is 0.70024×10^23
55.9 not mole it is weight so right answer is 0.70024×10^23
yes I am right
Similar questions