how many bullets can be made out of a cube of lead whose edge measures 22cmeach bullet being 2cm in diameter
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Answered by
27
Vol of cube = 22*22*22
=10648cm³
Vol of bullet = vol of sphere = 4/3πr³
= 4/3*22/7*1*1*1
=4.1cm³
Total bullets = 10648/4.1
= 2597 bullets
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but you have taken the radius as 2 cm only
please correct your answer
Afterall u have reported i cant correct it.
wait
you may get the edit option
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wat? :(
the moderators will give u tbe edit option to edit ur answer
hmmmm
wrong answer again
Answered by
50
It is based on the concept of volumes.
In order to find the number of bullets, that can be made out of a cube of edge 22 cm, we have to divide the cube's volume by the bullet's volume.
Edge of cube=22 cm
Its volume=a³
=22³
=10648 cm³
So, cube's volume=10648 cm³
Now, diameter of bullet=2 cm
Its radius=D/2=2/2=1 cm
So, its volume=4/3πr³
=4/3×22/7×1³
=4/3×22/7
=88/21 cm³
Now, the number of bullets, that can be made out of a cube of lead of edge 22 cm=cube's volume/bullet's volume
=10648 cm³÷88/21 cm³
=2541
So, the number of bullets that can be made out of a cube of lead of edge 22 cm is 2541
In order to find the number of bullets, that can be made out of a cube of edge 22 cm, we have to divide the cube's volume by the bullet's volume.
Edge of cube=22 cm
Its volume=a³
=22³
=10648 cm³
So, cube's volume=10648 cm³
Now, diameter of bullet=2 cm
Its radius=D/2=2/2=1 cm
So, its volume=4/3πr³
=4/3×22/7×1³
=4/3×22/7
=88/21 cm³
Now, the number of bullets, that can be made out of a cube of lead of edge 22 cm=cube's volume/bullet's volume
=10648 cm³÷88/21 cm³
=2541
So, the number of bullets that can be made out of a cube of lead of edge 22 cm is 2541
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