Physics, asked by amlesh, 1 year ago

how many capacitor of 4uF capacity each are combined to get total capacity of 6uF ?

Answers

Answered by ayush579
1
The voltage ( Vc ) connected across all the capacitors that are connected in parallel is THE SAME. Then, Capacitors in Parallel have a “common voltage” supply across them giving:

VC1 = VC2 = VC3 = VAB = 12V

In the following circuit the capacitors, C1, C2and C3 are all connected together in a parallel branch between points A and B as shown.



When capacitors are connected together in parallel the total or equivalent capacitance, CT in the circuit is equal to the sum of all the individual capacitors added together. This is because the top plate of capacitor, C1 is connected to the top plate of C2 which is connected to the top plate of C3 and so on.

The same is also true of the capacitors bottom plates. Then it is the same as if the three sets of plates were touching each other and equal to one large single plate thereby increasing the effective plate area in m2.

Since capacitance, C is related to plate area ( C = ε A/d ) the capacitance value of the combination will also increase. Then the total capacitance value of the capacitors connected together in parallel is actually calculated by adding the plate area together. In other words, the total capacitance is equal to the sum of all the individual capacitance’s in parallel. You may have noticed that the total capacitance of parallel capacitors is found in the same way as the total resistance of series resistors.

The currents flowing through each capacitor and as we saw in the previous tutorial are related to the voltage. Then by applying Kirchoff’s Current Law, ( KCL ) to the above circuit, we have



and this can be re-written as:



Then we can define the total or equivalent circuit capacitance, CT as being the sum of all the individual capacitance’s add together giving us the generalized equation of:

Parallel Capacitors Equation


rohit710: It's Copied
Answered by kishanpentyala
1
connect \: two \: capacitors \: in \: series \: first \\ and \: combination \: is \: connected \\ parallel \: to \: another \: capacitor. \\ \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} (in series)\\ \frac{1}{c} = \frac{1}{4} + \frac{1}{4} \\ c = 2 \\ c .\: t = c + 4(in \: parallel \: with \: another \: capacitor) \\ c.t = 2 + 4 = 6uf.
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