Question

How Many cubs having side of 5cm can be arranged in the cuboid box measuring 30cm x 20cm x 10cm​

Answer 1

Answer:

48

SIMPLE EXPLAIN

Total number of cubes = (30×20×10)/(5×5×5) = 48

Step-by-step explanation:

As per the question,

Given a cuboidal box having dimensions 30 cm x 20 cm x 10.

That is,

Length = 30 cm

Breadth = 20 cm

Height = 10 cm

As we know that volume of the cube is given by formula,

V = l × b × h

∴ Volume of cuboidal box =  l × b × h

= 30 cm x 20 cm x 10

= 6000 cm³

Now,

Smaller cube of side = 5 cm

Let the total number of small cube = n

∴ Total volume = 125n =6000

125n = 6000

n =  48

Hence, number of small cubes that can be arranged = 48.

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