Question

how many diagonals are there in each of the following 1) a convex Pentagon 2) a regular nonagan 3)a triangle 4) aheptagon ​

Answer 1

Answer:

Hey mate! Here are your answers:

Step-by-step explanation:

We have to use the formula {n(n - 3)}/2 where n is the number of sides to find the number of diagonals.

1) n = 5.

{5(5 - 3)} / 2

{5 * 2} / 2

10/2 = 5.

So a Convex Pentagon has 5 diagonals.

2) n = 9.

{9(9 - 3)} / 2

{9 * 6} / 2

54/2 = 27.

So a Nonagon has 27 diagonals.

3) n = 3.

{3(3 - 3)} / 2

{3 * 0} / 2

0/2 = 0.

So a Triangle has 0 diagonals.

4) n = 7.

{7(7 - 3)} / 2

{7 * 4} / 2

28/2 = 14.

So a Heptagon has 14 diagonals.

HOPE IT HELPS YOU, PLS MARK IT AS THE BRAINLIEST AND PLS FOLLOW ME! :):):)

Answer 2

Step-by-step explanation:

convex pentagon.......5 diagonals

triangle .....no diagonal

a regular nonagon........27 diagonals

a heptagon......14 diagonals