How many different words can be formed with the letters of the word equation without changing the relative order of the vowels and consonants?
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5 vowels can be arranged in their 5 particular places in 5! ways, and 3
consonents can be arranged in their 3 particular places in 3! ways.
Therefore, total ways = 5!3! = 720.
Hopes it helps have a nice day!
Therefore, total ways = 5!3! = 720.
Hopes it helps have a nice day!
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Answer:
5 vowels can be arranged in their 5 particular places in 5! ways, and 3 consonents can be arranged in their 3 particular places in 3! ways.
Therefore, total ways = 5!3! = 720.
Hopes it helps have a nice day!
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