how many g atoms of Hare present in 1.7g NH3
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g - atoms = moles
so no. of moles of NH3 = 1.7/17 = 0.1
1 mole of NH3 has 3 moles of H
0.1 mole of NH3 will have 0.3 moles of H
so no. of moles of NH3 = 1.7/17 = 0.1
1 mole of NH3 has 3 moles of H
0.1 mole of NH3 will have 0.3 moles of H
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