Question

How many gram atoms are present in one amu of Mg?

Answer 1

avogadro constant / molar mass of mg

Answer 2

Answer: $0.069\times 10^{-24}$

Explanation: Atomic mass unit (amu) is used to define the atomic mass of the substance.

1 amu= $1.66\times 10^{-24}g$

Thus given mass= $1.66\times 10^{-24}g$

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Number of moles}=\frac{1.66\times 10^{-24}g}{24g/mol}=0.069\times 10^{-24}$

Now 1 mole of a substance = 1 gram atom

$0.069\times 10^{-24}$  moles of a substance =$\frac{1}{1}\times 0.069\times 10^{-24}=0.069\times 10^{-24}$ gram atom