Question

How many gram of oxygen are produced by the decomposition of 145 gram of potassium chlorate

Answer 1

2KClO3→2 KCI +3O2

MASS OF KCIO3=122.5gm

= 145 gm = 1.18 moles

by stoichiometry, 2KCIO3→3 O2

2 KCIO3→3O2

1KCIO3→3/2 O2

SO, 1.18 KCIO3→1.18x3/2 O2

=1.17 MOLES OF O2

THEREFORE 1.17 x 18 = 21.06 gm

21.06 gm

hope it helps