Chemistry, asked by Shubhangee7005, 9 months ago

How many grams are present in 4000 amu of calcium

Answers

Answered by sreeh123flyback

2

Explanation:

1 amu is 1.66×10^-24 g

4000amu =4000×1.66×10^24

=6640×10^-24 grams

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