If for a gp t3=20 t7=320 then t10=?
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Answered by
4
Answer:
T3=ar^2 =20, T7=ar^6=320
T7/T3=r^4=16 then r=2, a=5
T10=a r^9=5(2^9)=5(512)=2560
Answered by
0
Answer:
see below
Step-by-step explanation:
T3=ar^2 =20, T7=ar^6=320
T7/T3=r^4=16 then r=2, a=5
T10=a r^9=5(2^9)=5(512)=2560
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