Question

How many grams of oxygen are required to burn completely 60 grams of ethane

Answer 1

Explanation:

60 gram of ethane = 60/30 moles = 2 moles

2C2H6 + 7O2 ------> 4CO2 + 6H2O

According to above equation

For 2 moles of ethane gas 7 moles of oxygen is required

It is asked to find weight of oxygen required to burn 60 g (2 moles) of ethane.

7 moles = 7 × 16 = 112 g

So 112 g of oxygen is required.