Question

how many maximum no. of electrons in a potassium atom satisfy l+m =0

Answer 1

Answer:

In an atom with atomic number 30 the total number of electrons having magnetic quantum number m=0?

94% placements. LLB online application form – apply now @ UPES.

In an atom of atomic number 30 the electronic configurtion is 1s(2) 2s(2) 2p(6) 3s(2) 3p(6) 4s(2) 3d(10).

The magnetic quantum number tells the orientation of different orbitals in space.

The magnetic quantum number for the s orbial is 0 as it is a spherical shape and has same orientation in every coordinates.

The possible magnetic quantum number for the p orbial is -1,0,1 as it can be oriented in three coordinates namely px,py,pz.

The possible magnetic quantum number for the d orbial is -2,-1,0,1,2 as it has five orientation namely d(xy),d(yz),d(zx),d(x^2-y^2),d(z^2).

In an atom of atomic number 30 the electronic configurtion is 1s(2) 2s(2) 2p(6) 3s(2) 3p(6) 4s(2) 3d(10) as mentioned above and every orbits are filled fully hence each orbit has a electron having magnetic quantum number ‘0’ hence total number is 7.

Explanation:

Please mark as the Brainliest answer....

Answer 2

The maximum number of electrons in a potassium atom satisfying l + m = 0 is 7.

• l Azimuthal quantum number of an atomic model is a quantum number that describes the state of the electron of an atom.
• m Magnetic quantum number determines the orientation of orbitals in a subshell. It depends on the value of l which ranges from -l to +l.
• ml = 0 for then l = 0, Therefore it describes the orientation of the s subshell.
• Potassium having atomic number 19 has the following electronic configurations: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s₁

So, total number of electrons in s subshell will be

⇒ 2 + 2 + 2 + 1 = 7

Therefore, maximum number of electrons satisfying l + m = 0 are 7 electrons.