How many mL of 0.125 M Cr3+ must be reacted with 12 mL of 0.2 M MnO4 -, if the redox products are CrO7 2- and Mn2+ ?
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Answer : 19.2 ml of reacted with .
Solution : Given,
Molarity of = 0.125 mole/L
Molarity of = 0.2 mole/L
Volume of = 12 ml = 0.012 L (1 L = 1000 ml)
The given chemical redox reaction is,
From the given reaction, we conclude that the 1 mole of react with the 1 mole of .
Formula used :
where,
= Molarity of
= Volume of
= Molarity of
= Volume of
Now put all the given values in above formula, we get the volume of .
Therefore, 19.2 ml of reacted with .
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