Question

How many mole of FeSO4 reacted with one mole KMnO4 in acidic medium?.

Answer 1

5 moles of $FeSO_4$ reacts with 1 mole of $KMnO_4$ in acidic medium.

Explanation:

• To find the number of moles involved in the reaction, a balanced chemical equation must be written.
• In the given case, the reactants are $FeSO_4$ , $KMnO_4$ and $H_2SO_4$ (as the medium is acidic).
• The chemical equation involved in the reaction is as follows:

$2KMnO_4 + 10FeSO_4+8H_2SO_4\rightarrow K_2SO_4+2MnSO_4+5Fe(SO_4)_3+8H_2O$.

• From the above-balanced equation it can be inferred that 2 moles of $KMnO_4$ reacts with 10 moles of $FeSO_4$.
• As 2 moles of $KMnO_4$ reacts with 10 moles of $FeSO_4$, 1 mole of $KMnO_4$ reacts with:

2 =10, 1 = x

When the values are cross multiplied

2x = 10

x = $\frac{10}{2}=5$

• Thus it can be inferred that 5 moles of $FeSO_4$ reacts with 1 mole of $KMnO_4$ in acidic medium.

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Answer 2

Answer:

Explanation:

To find the number of moles involved in the reaction, a balanced chemical equation must be written.

In the given case, the reactants are , and (as the medium is acidic).

The chemical equation involved in the reaction is as follows:

.

From the above-balanced equation it can be inferred that 2 moles of reacts with 10 moles of .

As 2 moles of reacts with 10 moles of , 1 mole of reacts with:

2 =10, 1 = x

When the values are cross multiplied

2x = 10

x =

Thus it can be inferred that 5 moles of reacts with 1 mole of in acidic medium

Explanation: