Question

How many mole of oxygen present in 128gm oxygen?

Answer 1

Hey there!

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✴ MOLE CONCEPT ✴

Oxygen is written as O.

Atomic Weight of Oxygen = 16 u.

Molar mass of Oxygen = 16 g.

This means ;

16 g of oxygen contains 1 mole of oxygen.

1 g of oxygen = 1 / 16 mole of oxygen atom.

128 g of oxygen = 1 / 16 × 128 moles.

$= > \frac{1}{ \cancel{ \: 16} \: {}^{1} } \times \cancel{ 128} \: {}^{8} \\ \\ = > 8$

Hence, 8 moles of oxygen is present in 128 g oxygen atom.

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Thanks for the question!