Question

How many molecules are present in 1.28g of SO2 gas, if the atomic mass of sulphur and oxygen is 32 u and 16 u respectively?

Answer 1

64 grams contains 6.023*10²³ molecules
1.28 grams contains ..................

molecules  = 1.28*6.023*10²³/64
molecules  = 1.2046*10²²

Answer 2

64gm = 6.023*10²³ molecules 1.28 grams contains molecules = 1.28*6.023*10²³/64 molecules = 1.2046*10²² PLZ MARK AS A BRAINLIEST. I NEEDED PLZ MARK AS A BRAINLIEST.