How many molecules are present in 1.28g of SO2 gas, if the atomic mass of sulphur and oxygen is 32 u and 16 u respectively?
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Answered by
3
64 grams contains 6.023*10²³ molecules
1.28 grams contains ..................
molecules = 1.28*6.023*10²³/64
molecules = 1.2046*10²²
1.28 grams contains ..................
molecules = 1.28*6.023*10²³/64
molecules = 1.2046*10²²
Answered by
2
64gm = 6.023*10²³ molecules
1.28 grams contains
molecules = 1.28*6.023*10²³/64
molecules = 1.2046*10²²
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