Chemistry, asked by vh0284246, 5 months ago

How many moles are present in 63.05 grams of glucose (C6H12O6) rounded to the nearest hundredth (2 decimal places) ?

Answers

Answered by raneedevi11

2

Answer:

0.35 moles

Explanation:

no. of moles= given mass/ molar mass

molar mass of C6H12O6 is 180 g

no. of moles= 63.05/180

=0.35 moles

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