How many moles are present in 63.05 grams of glucose (C6H12O6) rounded to the nearest hundredth (2 decimal places) ?
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Answer:
0.35 moles
Explanation:
no. of moles= given mass/ molar mass
molar mass of C6H12O6 is 180 g
no. of moles= 63.05/180
=0.35 moles
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