How many moles of dioxygen is present in 64 g of dioxygen
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Explanation:
We assume standard state conditions, under which regime we deal with O2 gas. Thus there are 64⋅g oxygen gas32⋅g⋅mol−1 = 2⋅mol .May 29, 2016
Answered by
2
Answer:
- We assume standard state conditions, under which regime we deal with O2 gas. Thus there are 64⋅g oxygen gas32⋅g⋅mol−1 = 2⋅mol ..
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