Question

How many moles of lead(||) chloride will be formed from a reaction between 6.5g of PbO & 3.2g of HCl

Answer 1

The equation for the reaction between PbO and HCl is as follows:

PbO + 2HCl------------> PbCl2  + Cl + H2O

Therefore 1 moles of PbO require 2 moles of HCl to give 1 mole of PbCl2.

Calculate the reagent, between HCl and PbO, that is the limiting reagent.

Pb-207.2  Cl-35.5  O-16  H-1

Moles=mass/molar mass

Moles of PbO  = 6.5/(207+16)  = 6.5/223.2  = 0.029148

If 1 mole = 2 moles of HCl 

Then,

0.029148= 2x0.029148= 0.058296

Moles of HCl= 3.2/(1+35.5) = 3.2/36.5  =  0.08767

If 2 moles of HCl=  1 mole of PbO

Then,

0.08767= 1x 0.8767/2  =  0.04384

Therefore PbO is the limiting reagent.

Calculate moles of PbCl2 produced as follows:

If 1 mole of PbO  = 1 mole of PbCl2

Then,

0.029148 will give=  1 x 0.029148 moles

Therefore moles of PbCl2 produced = 0.029148 moles