How many moles of magnesium phosphate, Mg₃(PO₄)₂ will contain 0.25 mole of oxygen atoms?
(A) 0.02
(B) 3.125 × 10⁻²
(C) 1.25 × 10⁻²
(D) 2.5 × 10⁻²
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Answer:
(B) 3.125 × 10⁻²
Explanation:
Magnesium phosphate = Mg3(PO4)2 (Given)
Mole of oxygen atoms = 0.25 (Given)
Thus,
One mole of Mg3(PO4)2 consist of 8 moles of oxygen atom = 1/8
x moles of Mg3(PO4)2 consist of 0.25 moles of oxygen atom = x/0.25
Therefore,
0.25 mole of oxygen = 1/8 × 0.25
= 3.125 × 10⁻²
Therefore, magnesium phosphate will contain 3.125 × 10⁻² moles.
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