How many moles of sodium chloride present in 250 ml of a 0.50M NaCL solution?
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Given, volume of solution is 250ml or 0.25 liter. So, number of mole of solute (NaCl) is 0.125mole present in solution . Hence, 7.3125 grams of sodium chloride is present in 250mL. Hence the amount of NaCl in the solution is 7.3125 g
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Answer: volume of solution is 250ml or 0.25 liter. So, number of mole of solute (NaCl) is 0.125mole present in solution . Hence, 7.3125 grams of sodium chloride is present in 250mL. Hence the amount of NaCl in the solution is 7.3125 g
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