How many n glyosidic bonds are present in phi *174 bacteriophage?
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Answered by
11
hey buddy !! here's your answer...
➡️phi 174 bacteriophage has 5386 nucleotides.
the N glycosidic bonds are present between nitrogen base and sugar . since each nucleotide has one such pair .
✔️therefore, there are 5386 bonds .
hope it helps !! ❤️✌️
➡️phi 174 bacteriophage has 5386 nucleotides.
the N glycosidic bonds are present between nitrogen base and sugar . since each nucleotide has one such pair .
✔️therefore, there are 5386 bonds .
hope it helps !! ❤️✌️
Answered by
0
Answer:
- a bacteriophage known as φ ×174 has 5386 nucleotides. a nitrogenous base is linked to the oh of 1' c pentose sugar through a n-glycosidic
- linkage to form a nucleoside.
- each nucleotide contains one glycosidic bond between pentose sugar and nitrogenous base. hence, possible number of glycosidic bonds in bacteriophase are 5386.
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